Regex -- using curly brackets

[nime5ter]

The regex cheatsheet that is mentioned in the wiki and in the regex action descriptions (http://www.mikesdotnetting.com/Article/46/CSharp-Regular-Expressions-Cheat-Sheet) includes a couple of regular expression operators that use curly brackets:

{n}   n is a non-negative integer. Matches exactly n times. For example, "o{2}" does not match the "o" in "Bob," but matches the first two o's in "foooood".
{n,}   n is a non-negative integer. Matches at least n times. For example, "o{2,}" does not match the "o" in "Bob" and matches all the o's in "foooood." "o{1,}" is equivalent to "o+". "o{0,}" is equivalent to "o*".
{n,m}   m and n are non-negative integers. Matches at least n and at most m times. For example, "o{1,3}" matches the first three o's in "fooooood." "o{0,1}" is equivalent to "o?".

Is it possible to use those in Vox, given that VC uses curly brackets for its variables?

[jitterjames]

You have to be careful.  If you try to use {2} in an expression, VC will try to replace it with payload 2.  If there is no payload 2 then it will leave it as is, so if you know your command is being executed without any payloads then you are free to use {2} in your expression.

If you know your command has a payload 2 attached to it, then you will need to avoid using the regex expression {2}.  This is relatively easy to do.

For example if you want to match exactly two digits using regex you can use any of the following patterns

Code Select Expand

\d\d

\d{2}

\d{2,2}

So you can use the first or the last option and just not use the middle one.

[nime5ter]

Okeydoke. Makes sense, thanks!